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The radius of a planet is R. A satellite...

The radius of a planet is `R`. A satellite revolves around it in a circle of radius `r` with angular velocity `omega_(0)`. The acceleration due to the gravity on planet's surface is

A

`(r^(3)omega)/(R)`

B

`(r^(2)omega^(3))/(R)`

C

`(r^(3)omega^(2))/(R^(2))`

D

`(r^(2)omega^(2))/(R)`

Text Solution

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The correct Answer is:
C
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