If a satellites is revolving close to a planet of density `rho` with period `T`, show that the quantity `rho T^(2)` is a universal constant.

A satellite of mass m is revolving close to surface of a plant of density d with time period T . The value of universal gravitational constant on planet is given by

A satellite is orbiting very close to a planet. Its periodic time depends only on

A satellite is orbiting just above the surface of a planet of average density D with period T . If G is the universal gravitational constant, the quantity (3pi)/G is equal to

If the period of revolution of an artificial satellite above the earth's surface be T and the density of earth be p, then prove that p T^(2) is a universal constant. Also calculate the value of this constant. Given G= 6.67xx10^(-11)m^(3) kg^(-1)s^(-2)

A satellite is orbiting just above the surface of the earth with period T. If d is the average density of the earth and G is the universal constant of gravitation, the quantity (3pi)/(Gd) represents its

When a satellite revolves around the sun in a circular orbit of radius a with a period of revolution T, and if K is a positive constant, then

If T is the period of a satellite revolving very close to the surface of the earth and if rho is the density of the earth, then

A satellite is orbiting around the earth with orbital radius R and time period T. The quantity which remains constant is

What is the periodic times of a satellite revolving very close to the surface of the earth, of density rho ?