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The density of the core a planet is rho(...

The density of the core a planet is `rho_(1)` and that of the outer shell is `rho_(2)`. The radii of the core and that of the planet are `R` and `2R` respectively. The acceleration due to gravity at the surface of the planet is same as at a depth `R`. Find the ratio of `(rho_(1))/(rho_(2))`

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The correct Answer is:
`[(rho_(1))/(rho_(2)) = 7/3]`
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