If m n, k are rational and m =k+k/n then...

If m n, k are rational and` m =k+k/n` then the roots of `x^2+mx+n=0` are

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`x+mx+n=0`
`x^2+(k+n/k)x+n=0`
`x=(-(k+n/k)pmsqrt((k+n/k)^2-4n))/2`
`x=(-(k+n/k)pmsqrt(k^2+n^2/k^2+2n-4n))/2`
`x=(-(k+n/k)pm(k-n/k))/2`
`x=-k,-n/k`.

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