`x^3+5x^2-2x-24 `,`x^3-4x^2+x+6`

Subtract: 2x^3-4x^2+3x+5 from 4x^3+x^2+x+6

If f(x)=|[3x^2-x+3,6x-1,4],[6x^2-4x+5,12x-4,8],[3x^2+2x+5,6x+2,4]|, then the degree of the polynomial f(x) is

(x^2+x-6)(x^2-3x-4)=24

What is the HCF of 36(3x^(4)+5x^(3)-2x^(2)) , 9(6x^(3)+4x^(2)-2x),54(27 x^(4)-x) ?

Factorise : 3x^5 - 6x^4 - 2x^3 + 4x^2 + x-2

Add the following expressions: (i) 8a-6a b+5b ,\ -6a-a b-8b\ a n d-4a+2a b+3b (ii) 5x^3+7+6x-5x^2,\ 2x^2-8-9x ,\ 4x-2x^2+3x^3,\ 3x^3-9x-x^2\ a n d\ x-x^2-x^3-4

Add the following expressions: (i) 8a-6a b+5b ,\ -6a-a b-8b\ a n d-4a+2a b+3b (ii) 5x^3+7+6x-5x^2,\ 2x^2-8-9x ,\ 4x-2x^2+3x^3,\ 3x^3-9x-x^2\ a n d\ x-x^2-x^3-4

Find the intervals in which the following function are increasing or decreasing. f(x)=10-6x-2x^2 f(x)=x^2+2x-5 f(x)=6-9x-x^2 f(x)=2x^3-12 x^2+18 x+15 f(x)=5+36 x+3x^2-2x^3 f(x)=8+36 x+3x^2-2x^3 f(x)=5x^3-15 x^2-120 x+3 f(x)=x^3-6x^2-36 x+2 f(x)=2x^3-15 x^2+36 x+1 f(x)=2x^3+9x^2+20 f(x)=2x^3-9x^2+12 x-5 f(x)=6+12 x+3x^2-2x^3 f(x)=2x^3-24 x+107 f(x)=-2x^3-9x^2-12 x+1 f(x)=(x-1)(x-2)^2 f(x)=x^3-12 x^2+36 x+17 f(x)=2x^3-24+7 f(x)=3/(10)x^4-4/5x^3-3x^2+(36)/5x+11 f(x)=x^4-4x f(x)=(x^4)/4+2/3x^3-5/2x^2-6x+7 f(x)=x^4-4x^3+4x^2+15 f(x)=5x^(3/2)-3x^(5/2),x >0 f(x)==x^8+6x^2 f(x)==x^3-6x^2+9x+15 f(x)={x(x-2)}^2 f(x)=3x^4-4x^3-12 x^2+5 f(x)=3/2x^4-4x^3-45 x^2+51 f(x)=log(2+x)-(2x)/(2+x),xR