`sqrt(sqrt( 16 sin^4 theta + cosec^4 theta + 8) -4) =`

If sin theta=4/5, cosec theta=?

If sin theta-cosec theta=sqrt5 then sin^2 theta+cosec^2 theta=

Prove each of the following identities : '(i) sin^(2)theta + cos^(4) theta = cos^(2) theta + sin^(4) theta (ii) "cosec"^(4) theta - "cosec"^(2) theta = cot^(4) theta + cot^(2) theta

If ' theta ' is in the III quadrant then sqrt(4 sin^(4) theta + sin^(2) 2 theta )+ 4 cos^(2)""((pi)/4-(theta )/(2))=

The value of 2 sec^(2) theta - sec^(4) theta - 2 cosec^(2)theta + cosec^(4) theta is

General solution of the equation 2 cot ^(2) theta + 2sqrt3 cot theta + 4 cosec theta + 8 =0 is

4sin 4theta -1 = sqrt(5)