(3times9^(n+1)-9times3^(2))/(3times3^(2n...

(3times9^(n+1)-9times3^(2))/(3times3^(2n+3)-9^(n+1))

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(3xx9^(n+1)-9xx3^(2n))/(3xx3^(2n+3)-9^(n+1))

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(9^(n)times3^(2)times3^(n)-(27)^(n))/((3^(3))^(5)times2^(3))=(1)/(27)," find the value of "n

(9^((1)/(3))times27^((-1)/(2)))/(3^((1)/(6))times3^((-2)/(3)))

(3^nxx9^(n+1))/(3^(n-1)xx9^(n-1))

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(3times9^(n+1)-9times3^(2))/(3times3^(2n+3)-9^(n+1))
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