[R-C-=C-H(NaNH_(2))/(rarr)ARX rarr B^(N)],[" The product 'C' is "]

In the reaction, Rxoverset(NaN_(3))rarr A overset(H_(2)//Pd-C)rarr B+N_(2) The product B is :

In the reaction , Ethyl bromide overset( KCN) (rarr) A overset(H^(+),H_(2)O)(rarr) B overset(LiAlH_(4))(rarr)C The product C is : The product is

In the reaction : CH_(3)-C-=C-Hoverset((i)NaNH_(2)//NH_(3)(I))rarr(A)overset(CH_(3)-CH_(2)-CH_(2)-Br)rarr (B) the product (B) is :

R-C -= C - H overset (NaNH_2)rarr A overset (RX)rarr B overset (Na//Liq NH_3)rarr C . The "product" 'C' is.

overset(Mg)rarr(A)overset((i)^(14)CO_(2))underset((ii)H^(+)//H_(2)O)rarr(B)overset(NaHCO_(3))rarr(C) gas, product C is :

. Hence, CH -= CH overset ((i) 1 mol of (NaNH_2 + liq. NH_3)) underset((ii)A)rarr ( C) . The product ( C) is :

Ph-underset(underset(Cl)(|))(CH)-CH_(2)-Cl underset(underset(("iii") H^(+))(("ii")NaNH_(2)))overset(("i")Alc.kOH)(rarr) A overset("Cold alk." KMnO_(4))(rarr)B underset("warm")overset("NaOH")(rarr)C The product 'C' eill be

Ph-underset(underset(Cl)(|))(CH)-CH_(2)-Cl underset(underset(("iii") H^(+))(("ii")NaNH_(2)))overset(("i")Alc.kOH)(rarr) A overset("Cold alk." KMnO_(4))(rarr)B underset("warm")overset("NaOH")(rarr)C The product 'C' eill be

In the reaction CH_3-C-=C-Hoverset((i) NaNH_2//NH_3(l))rarr(A)overset(CH_3-CH_2-CH_2-Br)rarr(B) The product B is