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( sin theta tan theta)/( 1- cos theta) =...

` ( sin theta tan theta)/( 1- cos theta) = 1 + sec theta`

Text Solution

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LHS
`(sin^2theta)/costheta*1/(1-costheta)*(1+costheta)/(1+costheta)`
`sin^2theta/(costheta(1-cos^2theta))*(1+costheta)`
`sin^2theta/sin^2theta*(1+costheta)/costheta`
`1+sectheta`
RHS.
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