`int1/(x(x^(3/2)+1))dx=2/3log(x^(3/2)/(x^(3/2)+1))+c`

int1/(x^(2)-x^(3))dx=

int1/(x^(2)-x^(3))dx=

int1/x^(2)(2x+1)^(3)dx=

int1/x^(2)(2x+1)^(3)dx=

int_1^3(x^2)/(x^3+1)dx=?

int3x^(1//2)(1+x^(3//2))dx

int_(1)^(3)(dx)/(x^(2)(x+1))=(2)/(3)+(log2)/(3)

int(x+1)/(x^(1//2)) dx= a) -x^(3//2)+x^(1//2)+c b) x^(1//2 c) 2/3x^(3//2)+2x^(1//2)+c d) x^(3//2)+x^(1//2)+c

int_1^9 (x^(3/2)+2x+3) dx