" (iii) "15x^(2)+53x_(1)+42=0

(i) 15x^(2) - 8x + 1 = 0 (ii) 6y^(2) - 19y + 10 = 0

Solve by the method of completing the square: (1) 9x^(2)-15x+6=0 (2) 5x^(2)-6x-2=0

Divide x^(3) - 12x^(2) + 0x - 42 by x^(2) - 2x + 1 .

If 3x^(2)-7x+2=0 and 15x^(2)-11x+a=0 have a common root and a is a positive real number then the sum of the roots of the equation 15x^(2) -ax +7=0 is

Write the quotient and remainder when we divide : (14x^(2) - 53x + 45) by (7x - 9)

x^(2)+15x+56=0

x^(2)-15x+54=0

15x^(2)-7x-36=0: