[2x+5y=1],[2x+3y=3]

x+5y=15;2x-3y=1

Prove that the following lines are concurrent. (i)5x-3y=1 , 2x+3y=23 , 42x+21y=257 (ii) 2x+3y-4=0 , x-5y+7=0 , 6x-17y+24=0

Solve by matrix method: 2x + 3y=1,4x+5y=3

Show that the lines 2x + 5y = 1, x - 3y = 6 and x + 5y + 2 = 0 are concurrent.

2x-y=1 ; 6x+3y=5

1 + 5x + 3y = 9 2x 3y = 12 X = (x, y) - 4

Evaluate : (2x - 5y)(2x+ 3y) for x = 2 and y = 3.

If 3x + 5y = 21 and 2x +3y = 13 , then find the values of x and y .

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))