`int(cos x)/(sin alpha)`

int(sin x)/(sin(x+alpha)dx)

int(cos x)/(cos(x+alpha))dx

int(sin x+cos x)/(sin(x -alpha))dx is equal to

int(sin x+cos x)/(sin(x -alpha))dx is equal to

int (cos x)/(cos (x+alpha))dx

int(sin xdx)/(sin(x-alpha))

Evaluate the following integrals: int (1)/(cos alpha x sin alpha)dx

int(cos2x-cos2 alpha)/(sin x-sin alpha)dx=

If x cos alpha + y sin alpha = x cos beta + y sin beta "then" (sin alpha - cos alpha - sin beta + cos beta)/(sin alpha + cos alpha - sin beta - cos beta)=