[" 12.A bus was moving with a speed of "54km" h.On applying brakes.it stopped in "8],[" seconds.Calculate the acceleration and the distance travelled before stopping."]

(a) Derive the formula : v= u+at , where the symbols have usual meanings. (b) A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.

A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.

A car is moving with a velocity of 72km/h. By applying brakes a negative acceleration of 0.4m/s2 is produced. the distance covered by the car before it stops?

A car of mass 480 kg moving at a speed of 54 km per hour is stopped in 10 s. Calculate the force applied by the brakes.

A train running at 108 km//h is brought to a halt in 2 minutes. Calculate the retardation produced by the application of brakes. Also, calculate the distance the train travels before stopping.

A car moving along a straight line at a speed of 72km/h stops in 5s. After the brakes are applied. Find the acceleration

A bus decreases its speed from 72 km//h to 54 km//h in 10 s . Calculate the acceleration of the bus.

A car moving with a speed of 50 km/hr can stopped by brakes, over a distance of 6 m. If the same car is moving at a speed of 100 km/hr. the stopping distance is

A truck is moving at a speed of 54 km/h. The radius of its wheels is 50 cm. On applying the brakes the wheels stop after 20 rotations. What will be the linear distance travelled by the truck during this? Also find the angular acceleration of the wheels.

A body of mass 10kg starting from rest, accelerates uniformly to a speed of 30m//s in 10s . Brakes are applied and the body stops in next 5 seconds , (figure). Calculate the accelerating force and the stopping force