If `f(n)=(int_0^n[x]dx)/(int_0^n{x}dx)`(where,[*] and {*} denotes greatest integer and tractional part of x and `n in N).` Then, the value of `f(4)` is...

Options

A. `x epsilon[0,1)`
B. `{x}=2`
C. `{x}=1//3`
D. `xgt0`

Explanation

`int_(0)^(x)[x]dx=int_(0)^(1)0dx+int_(1)^(2)1dx+int_(2)^(3)2dx+…………….`
`+int_([x]-1)^([x])([x]-1)dx+int_([x])^(x)[x]dx`
`=0+1+2+3+……….+([x]-1)+[x](x-[x])`
`=(([x]-1)[x])/2+[x]{x}`…………..1
Now `int_(0)^([x]) dx=[(x^(2))/2]_(0)^([x])=([x]^(2))/2`..............2
Comparing 1 and 2 we get
`([x]-1)[x])/2+[x]{x}=([x]^(2))/2`
`:.[x]^(2)-[x]+2[x]{x}=[x]^(2)`
`=[x]=0` or `{x}=1//2`