(7>(x)/(3)+(y)/(4)=11)/((5x)/(6)-(y)/(3)=-7)

Solve the following system of equations: (x)/(3)+(y)/(4)=11,quad (5x)/(6)-(y)/(3)=-7

Solve for x and y : x+(y)/(4)=11," "(5x)/(6)-(y)/(3)=7

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

Solve by the method of elimination 2x-y=3,3x +y=7 (ii) x-y=5, 3x+ 2y = 25 (iii) (x)/(10 ) +(y)/(5) =14 ,(x)/( 8) + (y)/( 6) =15 (iv) 3(2x+y) =7xy,3 (x+3y ) =11xy (v) (4)/(x) +5y =7,(3)/(x) +4y =5 (vi) 13x +11y = 70,11x +13y =74

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

The perpendicular distance from the origin to the plane containing the two lines,(x+2)/(3)=(y-2)/(5)=(z+5)/(7) and (x-1)/(1)=(y-4)/(4)=(z+4)/(7) is: (a) 11sqrt(6)(b)(11)/(sqrt(6))(c)11(d)6sqrt(11)

Add the following (8)/(5)x+(11)/(7)y+(9)/(4)xy,-(3)/(2)x-(5)/(3)y-(9)/(5)xy

Solve using Cramer's rule: (4)/(x+5)+(3)/(y+7)=-1&(6)/(x+5)-(6)/(y+7)=-5

If x:y=1:1, then (3x+4y)/(5x+6y)=(7)/(11) (b) (17)/(11)(17)/(23)(d)(4)/(5)

Solve : (4)/(x)+(5)/(y)=7 , (3)/(x)+(4)/(y)=(11)/(2) .