(v)(x+2)^(2)-121=0

In the following questions two equation numbered I and II are given You have to solve both equations and . . . . . (i) x-sqrt(121)=0 (ii) y^(2)-121=0

x- sqrt121=0, y^(2) - 121= 0

(x^(2)+9x-22)/(x^(2)-121) ÷ (2-x) The expression above is equivalent to

Find the no of zeros in expression: (3^(123)-3^(122)-3^121)(2^(122)-2^(121)-2^(120))

Find the no. of zeros in expression : (3^(123)-3^(122)-3^(121))(2^(121)-2^(120)-2^(119))

sqrt([(12.1)^(2)-(8.1)^(2)]-:[(0.25)^(2)+(0.25)(19.95)])

The number of common tangents to x^(2)+y^(2)=256 , (x-3)^(2)+(y-4)^(2)=121 is

The number of common tangents to x^(2)+y^(2)=256 (x-3)^(2)+(y-4)^(2)=121 is

The number of common tangents to x^(2)+y^(2)=256, (x-3)^(2)+(y-4)^(2)=121 is