`y=(x-a)^3(x-b)^3,` then

If A=(x^3+y^3)/((x-y)^2+3xy), B=((x+y)^2-3xy)/(x^3-y^3), C=(xy)/(x^2-y^2) then (A-:B)xxC=

(x+y)^(3)-(x-y)^(3) can be factorized as 2y(3x^(2)+y^(2)) (b) 2x(3x^(2)+y^(2))2y(3y^(2)+x^(2)) (d) 2x(x^(2)+3y^(2))

If [(x+y,a+b),(a-b,x-y)]=[(5-1),(3-5)] the the values of x, y, a, b are respectively.

If a = x+y, b=x-y and c = x+2y , then show that a^3+b^3+c^3-3abc =7y^2(3x+2y)

If x= a cos^3 t, y= a sin^3 t, then dy/dx=..... A) -y/x B) - (y/x)^(1/3) C) (y/x)^3 D) - (y/x)^3

Factorize : (i)(a-b)^3+(b-c)^3+(c-a)^3 (ii) x^3(y-z)^3+y^3(z-x)^3+z^3(x-y)^3

If (x_1-x_2)^2+(y_1-y_2)^2=a^2,(x_2-x_3)^2+(y_2-y_3)^2=b^2 and (x_3-x_1)^2+(y_3-y_1)^2=c^2 then prove that 4|{:(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1):}|= (a+b+c)(b+c-a)(c+a-b)(a+b-c)

(x+y)^3−(x−y)^3 can be factorized as (a) 2y(3x^2+y^2) (b) 2x(3x^2+y^2) (c) 2y(3y^2+x^2) (d) 2x(x^2 +3y^2)