If `2(costheta+cos2theta)+sin2theta(1+2costheta)=2sintheta`, `theta in[-pi,pi]` then

Solve: costheta+sintheta=cost2theta+sin2theta

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta) =

(sintheta+sin2theta)/(1+costheta+cos2theta)=?

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

Prove that (1-costheta +cos2theta )/(sin2theta -sintheta)=cottheta

int(cos2theta)/((sintheta+costheta)^2)d theta is equal to

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

If f(theta)=|{:(cos^2theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta," "0):}| , then find the value of f((pi)/6) .