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sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2...

`sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2`

Text Solution

Verified by Experts

`L.H.S. = sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)`
`=(1/2)^2+(1/2)^2-1^2 `
`=1/4+1/4-1`
`=1/2 - 1`
`=-1/2 = R.H.S.`
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