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If f(x)=(x^2-6x+3)/(x-1), what is f(-1) ...

If `f(x)=(x^2-6x+3)/(x-1)`, what is f(-1) ?

A

`-5`

B

`-2`

C

2

D

5

Text Solution

AI Generated Solution

The correct Answer is:
To find \( f(-1) \) for the function \( f(x) = \frac{x^2 - 6x + 3}{x - 1} \), we will substitute \( x = -1 \) into the function and simplify. ### Step-by-step Solution: 1. **Substitute \( x = -1 \) into the function:** \[ f(-1) = \frac{(-1)^2 - 6(-1) + 3}{-1 - 1} \] 2. **Calculate the numerator:** - First, calculate \( (-1)^2 \): \[ (-1)^2 = 1 \] - Next, calculate \( -6(-1) \): \[ -6(-1) = 6 \] - Now, add these results along with 3: \[ 1 + 6 + 3 = 10 \] 3. **Calculate the denominator:** \[ -1 - 1 = -2 \] 4. **Combine the results:** \[ f(-1) = \frac{10}{-2} = -5 \] ### Final Answer: Thus, \( f(-1) = -5 \).
To find \( f(-1) \) for the function \( f(x) = \frac{x^2 - 6x + 3}{x - 1} \), we will substitute \( x = -1 \) into the function and simplify. ### Step-by-step Solution: 1. **Substitute \( x = -1 \) into the function:** \[ f(-1) = \frac{(-1)^2 - 6(-1) + 3}{-1 - 1} \] ...
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