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ax^3 + bx^2+cx +d =0 In the equation a...

`ax^3 + bx^2+cx +d =0`
In the equation above, a, b, c, and d are constants. If the equation has roots −1, −3, and 5, which of the following is a factor of `ax^3 + bx^2 + cx + d` ?

A

x-1

B

x+1

C

x − 3

D

x+5

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the following is a factor of the polynomial \( ax^3 + bx^2 + cx + d = 0 \) given that the roots are \( -1, -3, \) and \( 5 \), we can follow these steps: ### Step 1: Understand the relationship between roots and factors If a polynomial has roots \( r_1, r_2, \) and \( r_3 \), then the polynomial can be expressed in factored form as: \[ a(x - r_1)(x - r_2)(x - r_3) \] where \( a \) is a non-zero constant. ### Step 2: Identify the roots The roots given in the problem are: - \( r_1 = -1 \) - \( r_2 = -3 \) - \( r_3 = 5 \) ### Step 3: Write the factors corresponding to the roots From the roots, we can write the factors: - For \( r_1 = -1 \), the factor is \( (x + 1) \) - For \( r_2 = -3 \), the factor is \( (x + 3) \) - For \( r_3 = 5 \), the factor is \( (x - 5) \) ### Step 4: List the factors Thus, the polynomial can be expressed as: \[ a(x + 1)(x + 3)(x - 5) \] This means that the factors of the polynomial \( ax^3 + bx^2 + cx + d \) include \( (x + 1) \), \( (x + 3) \), and \( (x - 5) \). ### Step 5: Identify the correct option Now, we need to check which of the provided options is a factor: - Option a: \( x - 1 \) (not a factor) - Option b: \( x + 1 \) (is a factor) - Option c: \( x - 3 \) (not a factor) - Option d: \( x + 5 \) (not a factor) The correct answer is **Option b: \( x + 1 \)**.

To determine which of the following is a factor of the polynomial \( ax^3 + bx^2 + cx + d = 0 \) given that the roots are \( -1, -3, \) and \( 5 \), we can follow these steps: ### Step 1: Understand the relationship between roots and factors If a polynomial has roots \( r_1, r_2, \) and \( r_3 \), then the polynomial can be expressed in factored form as: \[ a(x - r_1)(x - r_2)(x - r_3) \] where \( a \) is a non-zero constant. ...
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