Home
Class 12
MATHS
h(t) = −16t^2 + 110t + 72 The functio...

h(t) = −`16t^2` + 110t + 72
The function above models the height h, in feet, of an object above ground t seconds after being launched straight up in the air. What does the number 72 represent in the function?

A

The initial height, in feet, of the object

B

The maximum height, in feet, of the object

C

The initial speed, in feet per second, of the object

D

The maximum speed, in feet per second, of the object

Text Solution

Verified by Experts

The correct Answer is:
A

The variable t represents the seconds after the object is launched. Since h(0) = 72, this, means that the height, in feet, at 0 seconds, or the initial height, is 72 feet. Choices B, C, and D are incorrect and may be the result of misinterpreting the function in context.
Promotional Banner

Similar Questions

Explore conceptually related problems

h(x)=-16x^2 + 100x+10 The quadratic function above models the height above the ground h, in feet, of a projectile x seconds after it had been launched vertically. If y = h(x) is graphed in the xy-plane, which of the following represents the real-life meaning of the positive x-intercept of the graph?

h=-16t^(2) + vt + k The equation above gives the height h, in feet, of a ball t seconds after it is thrown straight up with an initial speed of v feet per second from a height of k feet. Which of the following gives v in terms of h, t, and k ?

The number of bacteria colonies h hours after the beginning of an experiment is given by the function C(h)=3^h-2h+20 . What does the number 20 represent in the function?

h(t)=-4.9t^(2)+68.6t The function above gives the height of a model rocket, in meters, t seconds after it is launched from ground level. What is the maximum height, to the nearest meter, attained by the model rocket?

h(t)=144t-16t^(2) The function above represents the height, in feet, a ball reaches t seconds after it is tossed in the air from groud level. a. What is the maximum height of the ball? b. After how many seconds will the ball hit the ground before rebounding?

h=-4.9t^(2)+25t The equation above expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground with an initial velocity of 25 meters per second. After approximately how many seconds will the ball hit the ground?

u=(1)/(2)at^(2) The velocity,v,of an object t seconds after beginning to accelerate from rest at a constant acceleration,a, can be found using the equation above. According to the formula, what is the ratio of velocity of the object t seconds after begins to accelerate to the velocity of the object 2.5t seconds after the object begins to accelerate?

A soccer ball is kicked upward from gound level with an initial velocity of 52 feet per second. The function h(t)=-16t^2+52t gives the ball's height , in feet , after t seconds. For how many seconds, to the nearest tenth of a second , is the ball at least 20 feet above the ground ?

d(t) = -16t^2+40t +24 A swimmer dives from a diving board that is 24 feet above the water. The distance, in feet, that the diver travels after t seconds have elapsed is given by the function above. What is the maximum height above the water, in feet, the swimmer reaches during the dive?