`y=x^2-4x+4`
y=4-x
If the ordered pair (x, y) satisfies the system of equations above, what is one possible value of x ?

Explanation

To solve the system of equations given by \( y = x^2 - 4x + 4 \) and \( y = 4 - x \), we will follow these steps:

1. **Set the equations equal to each other**: Since both equations equal \( y \), we can set them equal to each other:
\[ x^2 - 4x + 4 = 4 - x \]

2. **Rearrange the equation**: Move all terms to one side of the equation to set it to zero:
\[ x^2 - 4x + 4 - 4 + x = 0 \]
Simplifying this gives:
\[ x^2 - 3x = 0 \]

3. **Factor the quadratic equation**: Factor out the common term \( x \):
\[ x(x - 3) = 0 \]

4. **Set each factor to zero**: This gives us two possible solutions:
\[ x = 0 \quad \text{or} \quad x - 3 = 0 \implies x = 3 \]

5. **Conclusion**: One possible value of \( x \) is \( 0 \) or \( 3 \).