g(x)=2x-1
h(x)=1-g(x)
The functions g and h are defined above. What is the value of h(0) ?

Options

A. `-2`
B. 0
C. 1
D. 2

Explanation

To find the value of \( h(0) \), we will follow these steps:

1. **Identify the functions**:
We have two functions defined as:
\[ g(x) = 2x - 1 \]
\[ h(x) = 1 - g(x) \]

2. **Substitute \( x = 0 \) into \( h(x) \)**:
We need to find \( h(0) \):
\[ h(0) = 1 - g(0) \]

3. **Calculate \( g(0) \)**:
Now we need to find \( g(0) \) using the function \( g(x) \):
\[ g(0) = 2(0) - 1 = 0 - 1 = -1 \]

4. **Substitute \( g(0) \) back into \( h(0) \)**:
Now we can substitute \( g(0) \) back into the equation for \( h(0) \):
\[ h(0) = 1 - (-1) = 1 + 1 = 2 \]

5. **Final answer**:
Thus, the value of \( h(0) \) is:
\[ \boxed{2} \]