Home
Class 12
MATHS
In the xy-plane, the graph of the polyno...

In the xy-plane, the graph of the polynomial function f crosses the x-axis at exactly two points, (a, 0) and (b, 0), where a and b are both positive. Which of the following could define f ?

A

f (x) = (x − a)(x − b)

B

f (x) = (x + a)(x + b)

C

f (x) = (x − a)(x + b)

D

f (x) = x(x − a)(x − b)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which polynomial function \( f \) crosses the x-axis at exactly two points, \( (a, 0) \) and \( (b, 0) \), where both \( a \) and \( b \) are positive, we need to analyze the given options. ### Step-by-step Solution: 1. **Understanding the Problem**: Since the polynomial crosses the x-axis at exactly two points, this means that \( f(a) = 0 \) and \( f(b) = 0 \). The polynomial must have roots at \( a \) and \( b \) and should not cross the x-axis at any other point. 2. **Form of the Polynomial**: A polynomial that crosses the x-axis at two distinct points can be represented as: \[ f(x) = k(x - a)(x - b) \] where \( k \) is a non-zero constant. This form ensures that the polynomial has roots at \( a \) and \( b \). 3. **Analyzing the Options**: We will evaluate each option to see if substituting \( a \) and \( b \) results in \( f(a) = 0 \) and \( f(b) = 0 \). - **Option A**: Check if \( f(a) = 0 \) and \( f(b) = 0 \). - **Option B**: Substitute \( a \) and \( b \) into the polynomial and check if it equals 0. - **Option C**: Similarly, substitute \( a \) and \( b \) and check. - **Option D**: Perform the same substitution. 4. **Substituting Values**: - For each option, substitute \( a \) and \( b \) into the polynomial and check if the result is zero. - If any option yields \( f(a) = 0 \) and \( f(b) = 0 \) without any additional roots, it is a candidate. 5. **Identifying the Correct Option**: - After evaluating all options, we find that: - **Option A** satisfies \( f(a) = 0 \) and \( f(b) = 0 \) without introducing any other roots. - Other options either introduce additional roots or do not satisfy the conditions. ### Conclusion: The polynomial function \( f \) that crosses the x-axis at exactly two points \( (a, 0) \) and \( (b, 0) \) is defined by **Option A**.

To determine which polynomial function \( f \) crosses the x-axis at exactly two points, \( (a, 0) \) and \( (b, 0) \), where both \( a \) and \( b \) are positive, we need to analyze the given options. ### Step-by-step Solution: 1. **Understanding the Problem**: Since the polynomial crosses the x-axis at exactly two points, this means that \( f(a) = 0 \) and \( f(b) = 0 \). The polynomial must have roots at \( a \) and \( b \) and should not cross the x-axis at any other point. 2. **Form of the Polynomial**: ...
Promotional Banner

Similar Questions

Explore conceptually related problems

If the graph above is that of f(x), which of the following could be f(x)?

The graph of the linear function f has intercepts at (a,0) and (0, b) in the xy-plane. If a+b=0 and a ne b , which of the following is true about the slope of the graph of f ?

The graphs shown above represent f(x) and f(x+a) + b, where a and b are constants. Which of the following is the ordered pair (a,b) ?

In the xy-plane, the graph of the functions g has zeros at -4, 2, and 4. Which of the following could define g?

In the xy-plane, the graph of function f has x-intercepts at -3, -1, and 1. Which of the following could define f ?

The graph of the linear function f has intercepts at (c,0) and (0,d) in the xy-plane. If 2c= d and d ne 0, which of the following in true about the slope of the graph of f ?

If in the quadratic function f(x)=ax^(2)+bx+c , a and c are both negative constant, which of the following could be the graph of function f?

The function f is defined by f(x)=x^4-4x^4 -x^2+cx -12 , where c is a constant.In the xy-plane, the graph of f intersects the x-axis in the four points (-2,0), (1,0), (p,0), and (q,0). What is the value of c ?

The graph of the function f in the xy-plane above is a parabola. Which of the following defines f ?