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If (cos)^y=(siny)^x , then (dy)/(dx) equ...

If `(cos)^y=(siny)^x` , then `(dy)/(dx)` equals

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Knowledge Check

  • If y^(cosx)=x^(siny)," then "(dy)/(dx)=

    A
    `(y(xsinxlogy+siny))/(x(cosx-ylogxcosy))`
    B
    `(y(xsinxlogx-siny))/(x(cosx+ylogxcosy))`
    C
    `(y(siny-xlogy))/(x(x-ycosy(logx)))`
    D
    `(y(siny+xlogy))/(x(x+ycosy(logx)))`

  • If siny=xsin(a+y) , then (dy)/(dx) is :

    A
    `(sina)/(sinasin^(2)(a+y))`
    B
    `(sin^(2)(a+y))/(sina)`
    C
    `sinasin^(2)(a+y)`
    D
    `(sin^(2)(a+y))/(sina)`

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