`2x^2+2sqrt(6)x y+3y^2`

The equation of a circle of radius 1 touching the circles x^2 + y^2 - 2 |x| = 0 is: (A) x^2 + y^2 + 2sqrt(3x) - 2 = 0 (B) x^2 + y^2 - 2sqrt(3)y+2=0 (C) x^2 + y^2 + 2sqrt(3) y + 2 = 0 (D) x^2 + y^2 + 2 sqrt(3) x + 2 = 0

If sqrt(1 - x^6) + sqrt(1 - y^6) = a^3 (x^3 - y^3) prove that (dy)/(dx) = (x^2 sqrt(1 - y^6))/(y^2 sqrt(1 - x^6))

Rationalise the denominator: (a) (1)/(root(3)(3) + root(3)(2)) , (b) (2)/(sqrt5 + sqrt3 + sqrt2) , (c) (x^(2))/(sqrt(x^(2) + y^(2)) - y) , (d) (1)/(sqrt6 + sqrt5 - sqrt11) (e) (sqrt(x + 2y) - sqrt(x -2y))/(sqrt(x + 2y) + sqrt(x - 2y)) , (f) (sqrt10 + sqrt5 - sqrt3)/(sqrt10 - sqrt5 + sqrt3)

Evaluate (sqrt(x^2-y^2)+x)/(sqrt(x^2+y^2)+y) divide (sqrt(x^2+y^2)-y)/(x-sqrt(x^2-y^2))

If 24 sqrt3 x^3+2 sqrt2 y^3=(2 sqrt3x+ sqrt2 y)(Ax^2+Bxy+Cy^2) , then the value of (2A+sqrt6 B-C) is: यदि 24 sqrt3 x^3+2 sqrt2 y^3=(2 sqrt3x+ sqrt2 y)(Ax^2+Bxy+Cy^2) है, तो (2A+sqrt6 B-C) का मान ज्ञात करें |

If the value of (3x sqrt y+2y sqrt x)/(3x sqrt y-2y sqrt x)-(3x sqrt y-2y sqrt x)/(3x sqrt y+2y sqrt x) is same as that of sqrt x sqrt y , then which of the following relations between x and y is correct? यदि (3x sqrt y+2y sqrt x)/(3x sqrt y-2y sqrt x)-(3x sqrt y-2y sqrt x)/(3x sqrt y+2y sqrt x) का मान sqrt x sqrt y के समान है, तो निम्नलिखित में से कौन सा संबंध x और y के बीच सही है?