From some instruments current measured is `I=10.0amp`, potential different measured is `V=100.0 V`, length of wire is `31.4 cm`, and diameter of wire is `2.00mm` (all in correct significant figure). The resistivity of wire (in correct significant figures)will be (use `pi=3.14`)
A
`1.00xx10^(-4)Omega-m`
B
`1.0xx10^(-4)Omega-m`
C
`1xx10^(-4)Omega-m`
D
`1.000xx10^(-4)Omega-m`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
GENERAL PHYSICS
DC PANDEY|Exercise MCQ_TYPE|17 Videos
GENERAL PHYSICS
DC PANDEY|Exercise MATCH THE COLUMN|6 Videos
FLUID MECHANICS
DC PANDEY|Exercise Medical entranes gallery|49 Videos
GRAVITATION
DC PANDEY|Exercise (C) Chapter Exercises|45 Videos
Similar Questions
Explore conceptually related problems
In an experiment, current measured is, 1 = 10.0 A , potential difference measured is V = 100.0 C , length of the wire is 31.4 cm and the diameter of the wire 2.00 mm (all in correct significant figures). Find resistivity of the wire in correct significant figures. [Take pi = 3.14 , exact]. (a) (b) (c) (d) .
Radius of a wire is 2.50 mm. The length of the wire is 50.0 cm. If mass of wire was measured as 25g, then find the density of wire in correct significant figures. [Given, pi = 3.14, exact]
A thin wire has a length of 21.7 cm and radius 0.46 mm. Calculate the volume of the wire to correct significant figures.
A thin wire has length of 21.7 cm and radius 0.46 mm. Calculate the volume of the wire to correct significant figures?
In the experiment of Ohm's law, when potential difference of 10.0 V is applied, current measured is 1.00 A. If length of wire is found to be 10.0cm and diameter of wire 2.50 mm, then find maximum permissible percentage error in resistivity.
If the length of wire is (100.0 cm) and radius of wire as measured from screw gauge is (1.00mm) then the specific resistance of wire material is .
