In an experiment refractive index of glass was observed to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. The mean absolute error in the experiement is
A
`+-0.04`
B
`0.02`
C
`-0.03`
D
`+-0.01`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
GENERAL PHYSICS
DC PANDEY|Exercise MCQ_TYPE|17 Videos
GENERAL PHYSICS
DC PANDEY|Exercise MATCH THE COLUMN|6 Videos
FLUID MECHANICS
DC PANDEY|Exercise Medical entranes gallery|49 Videos
GRAVITATION
DC PANDEY|Exercise (C) Chapter Exercises|45 Videos
Similar Questions
Explore conceptually related problems
In an experiment the refractive index of glass was observed to be 1.45 , 1.56 , 1.54 , 1.44 , 1.54 , and 1.53 . Calculate (a). Mean value of refractive index (b). Mean absolute error ( c ) Fractional error (d) Percentage error (e) Express the result in terms of absolute error and percentage error
In an experiment, the values of refractive indices of glass were found to be 1.54, 1.53, 1.44, 1.54, 1.56 and 1.45 in successive measurements (i) mean value of refreactive index of glass (ii) mean absolute error (iii) relative error and (iv) percentage error are respectively.
The refractive index (n) of glass is found to have the values 1.49,1.50,1.52,1.54 and 1.48. Calculate (i) the mean value of refractive index, (ii) absolute error in each measurement, (iii) mean absolute error, (iv) fractional error and (v) percentage error
Repeated observations in an experiment gave the values 1.29 , 1.33 , 1.34 , 1.35 , 1.32 , 1.36, 1.30, and 1.33 . Calculate the mean value, absolute eror , relative error, and percentage error.
The refractive index of glass is 1.5. The speed of light in glass is
If refractive index of glass is 1.50 and of water is 1.33, then criticle angle is
The refraction index of glass is 1.5. Find the speed of light in glass.
In Rutherford's experiment , scattering of more than 1^@ was observed in