The `|u|,|v|` graph for a concave mirror is a shown in figure. Here `|u|gt|f|`. A line passing through origin of slope 1 cut the graph at point `P`. Then co-ordinate of point `P` are
A
`(|2f|,|2f|)`
B
`(|2f| ,|f|)`
C
`(|f|,|2f|)`
D
`(|f|,|f|)`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
GENERAL PHYSICS
DC PANDEY|Exercise MCQ_TYPE|17 Videos
GENERAL PHYSICS
DC PANDEY|Exercise MATCH THE COLUMN|6 Videos
FLUID MECHANICS
DC PANDEY|Exercise Medical entranes gallery|49 Videos
GRAVITATION
DC PANDEY|Exercise (C) Chapter Exercises|45 Videos
Similar Questions
Explore conceptually related problems
P – V graph for a cyclic process is shown in figure . Work done is given by
The slope of a line passing through origin and a point (3,4) is.......
The graph of the line x=3 passes through the point
The graph of the line y=3 passes through the point
Find the equation of a plane passes through the point (1,2,3) and cuts equal intercepts on the co-ordinate axes.
In the figure , point P is the centre of the circle and AB is the diameter . The co-ordinates of A are
The graph between (1)/(v) and (1)/(u) for a concave mirror looks like.