A particle moves move on the rough horiz...

A particle moves move on the rough horizontal ground with some initial velocity `V_(0)`. If `(3)/(4)` of its kinetic enegry lost due to friction in time `t_(0)`. The coefficient of friction between the particle and the ground is.

`(v_(0))/(2g t_(0))`

`(v_(0))/(4g t_(0))`

`(3v_(0))/(4g t_(0))`

`(v_(0))/(g t_(0))`

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