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Velocity of a particle moving in a curvi...

Velocity of a particle moving in a curvilinear path varies with time as `v=(2t hat(i)+t^(2) hat(k))m//s`. Here t is in second. At `t=1` s

A

acceleration of particle is `8 m//s^(2)`

B

tangential acceleration of particle is `(6)/(sqrt(5)) m//s^(2)`

C

radial acceleration of particle is `(2)/(sqrt(5))m//s^(2)`

D

radius of curvature to the path is `(5 sqrt(5))/(2)m`

Text Solution

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The correct Answer is:
B, C, D
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