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Moment of inertia of a straight wire abo...

Moment of inertia of a straight wire about an axis perpendicular to the wire passing through one of its end is I.
Now the same wire is bent into a ring of two turns , then the moment of inertia would be

A

`((pi^(2))/(3))l`

B

`((pi^(2))/(12))l`

C

`((3)/(16pi^(2)))l`

D

`((3)/(4pi^(2)))l`

Text Solution

Verified by Experts

The correct Answer is:
C
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