The mass of a rocket is 500 kg and the relative velocity of the gases ejecting from it is 250 m/s with respect to the rocket. The rate of burning of the fuel in order to give the rocket an initial acceleration `20 m//s^(2)` in the vertically upward direction `g = 10 m/s^(2)`, will be -

In a rocket of mass 1000 kg fuel is consumed at a rate of 40 kg/s . The velocity of the gases ejected from the rocket is 5xx10^(4)m//s . The thrust on the rocket is

A rocket of mass 1000 kg is to be projected vertically upwards. The gases are exhausted vertically downwards with velocity 100m//s with respect to the rocket. (What is the minimum rate of burning fuel, so as to just lift the rocket upwards against the gravitational attraction?) (Take g=10m//s^(2) )

If M is mass of rocket, r is rate of ejection of gases and u is velocity of gases with respect to rocket then acceleration of the rocket dv/dt is equal to

The exhaust velocity of gases with respect to a small rocket of mass 25 kg. is 28xx10^(2)m//s . At what rate the fuel must burn so that it may rise up with an acceleration of 9.8 m//s^(2) ?

If the force on a rocket moving with a velocity of 300m/s is 345 N, then the rate of combustion of the fuel is

For a Rocket propulsion velocity of exhaust gases relative to rocket is 2km/s. If mass of rocket system is 1000 kg, then the rate of fuel consumption for a rockt to rise up with acceleration 4.9 m//s^(2) will be:-

A rocket of mass 5000 kg is to be projected vertically upward. The gases are exhausted vertically downwards with velocity 1000ms^(-1) with respect to the rocket. What is the minimum rate of burning the fuel so as to just lift the rocket upwards against gravitational attraction ?