If the maximum possible exhaust velocity of a rocket be `2km//s` calculate the ratio `m_(0)//m` for it to acquire a veocity of `11.2km//s` after starting from rest .

Calculate the ratio m_(0)//m for a rocket to attain the escape velocity of 11.2km s^(-1) after starting from rest, when maximum exhaust velocity of gases is 1.6km//s .

A rocket of mass 20kg has 180kg fuel. The exhaust velocity of the fuel is 1.6km//s . Calculate the minimum rate of consumption of fuel so that the rocket may rise from the ground. Also, calculate the ultimate vertical speed gained by the rocket when the rate of consumption of fuel is (g=9.8m//s^2) (i) 2kg//s (ii) 20kg//s

Escape velocity of a rocket is 11.2 km/sec. It is released at an angle of 45^(@) . Its escape velocity is

Calculate the ration m _(0)//m for a rocket if it is to escape from the earth . Given escape velocity = 11.2 km//s and exhaust speed of gases is 2 km// s .

If acceleration of a particle at any time is given by a = 2t + 5 Calculate the velocity after 5 s, if it starts from rest

The velocity v of mass m of a rocket at time t is given by the equation : m (dv)/(dt)+V (dm)/(dt)=0 , where 'V' is the constant velocity of emission. If the rocket starts from rest when t=0 with mass m, prove that : v= V log ((m_(0))/(m)) .

A rocket motor consumes one quintal of fuel per secound . The exhaust speed of gases w.r.t roket is 5 km //s Calculate the force exerted on the rocket. What is the velocity acquired by the rocket , when its mass reduces to 1//100 th of its initial mass ?.