A mass of 6 kg is suspended by a rope of length 2 m from the ceilling A force of 50 N in the horizontal direction is applied at the mid - point P of the rope as shown . What is the angle the rope makes with the vertical in equilibrium ? (Take = `10 ms^(-2)`) . Neglect mass of the rope .

A mass of 20 kg is suspended by a rope of length 2 m from a ceiling. A force of 173.2 N in the horizontal direction is applied at the midpoint of the rope as shown in Fig. What is the angle the rope makes with the horizontal in equilibrium ? Take g = 10 ms^(-2) . Neglect mass of the rope.

A mass of 4kg is suspended by a rope of length 4m from a ceiling. A force of 20N in the horizontal direction is applied at the mid-point of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g=10ms^(-2) .

A mass of 3kg is suspended by a rope of length 2m from the ceilling A force of 40N in the horizontal direction is applied atmidpoint P of the rope the as shown. What is the angle the rope makes with the vertical in equilibrium and the tension in part of string attached to the ceiling ? (Neglect the mass of the rope, g =10m//s^(2)) .

A mass of 6 kg is suspended by a rope of length 2m from a celling. A force of 50N is applied in horizontal direction at the mid point of the rope. What is the angle of the rope with the verticle in equilibrium:-

A block fof mass 5kg is suspended by a massless rope of length 2 m from the ceilling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is (Take g=10ms^(-2)m .

A mass of 10kg is suspended by a rope of length 2.8m from a ceiling. A force of 98N is applied at the midpoint of the rope as shown in figure. The angle which the rope makes with the vertical in equilibrium is .

A mass of 20 kg is suspended by a rope of length 4 m from the ceiling. A force of 60 N is applied at the midpoint of the rope in the horizontal direction. What is the angle made by the rope with the vertical in equilibrium? Assume that the mass of the rope is negligible and g=10m//s^(2)

A mass of 10 kg is suspended vertically by a rope of length 2 m from a ceiling. A force of 60 N is applied at the middle point of the rope in the horizontal direction, as shown in Fig. Calculate the angle the rope makes with the vertical. Neglect the mass of the rope and take g =10ms^(-2) .