A horizontal force of 500 N pulls two masses 10 kg and 20 kg (lying on a frictionless table) connected by a light string. What is the tension in the string ? Does the answer depend on which mass end the pull is applied?

Two block of masses m_(1) and m_(2) are lying on a frictionless horizontal table connected by a light string m_(2) is pulled by horizontal force F. Calculate the tension in the string .

A string of length L and mass M is lying on a horizontal table. A force F is applied at one of its ends. Tension in the string at a distance x from the end at which force is applied is

Two blocks each of mass m are connected over two light and frictionless pulleys and a fixed wedge by a light string as shown in figure. The tension in the string is :

Two blocks of masses of 40 kg and 30 kg are connected by a weightless string passing over a frictionless pulley as shown in the figure.

Two masses of 10 kg and 20 kg are connected with an inextensible string passing over two smooth pulleys as shown in the figure. The acceleration of 20 kg mass will be :

Two blocks A and B each of 20 kg lying on a frictionless table are connected by a light string. The system is pulled horizontally with an acceleration of 2 ms ^ ( - 2 ) by a force F on B. The tension in the string will be

Three metal blocks A , B and C of masses 10 kg , 20 kg and 30 kg rest on a frictionless table in a line . A is converted to B and B to C by two pieces of string . With the help of a third string attached to C , the system is pulled to the right with a force of 60 N . Find the tensions of the first and second strings .