In terms of masses `m_(1),m_(2)` and g, find the acceleration of both the blocks shown in Fig. Neglect all friction and masses of the pulley.

In the fig, find the acceleration of mass m_(2) .

Find the acceleration of the block of mass m. Assume pulleys are massless and frictionless.

Three blocks of masses m_(1), m_(2) and M are arranged as shown in figure. All the surfaces are fricationless and string is inextensible. Pulleys are light. A constant force F is applied on block of mass m_(1) . Pulleys and string are light. Part of the string connecting both pulleys is vertical and part of the strings connecting pulleys with masses m_(1) and m_(2) are horizontal. {:((P),"Accleration of mass " m_(1),(1) F/(m_(1))),((Q),"Acceleration of mass" m_(2),(2) F/(m_(1)+m_(2))),((R),"Acceleration of mass M",(3) "zero"),((S), "Tension in the string",(4) (m_(2)F)/(m_(1)+m_(2))):}

Three blocks of masses m_1, m_2 and m_3 are connected as shown in the figure. All the surfaces are frictionless and the string and the pulleys are light. Find the acceleration of m_1

Two block of masses m_(1) and m_(2) are in equilibrium. The block m_(2) hangs from a fixed smooth pulley by an inextensible string that is fitted with a light spring of stiffness k as shown in fig. Neglecting friction and mass of the string, find the acceleration of the bodies just after the string S is cut.

In the arrangement shown in Figure, m_A=2kg and m_B=1kg . String is light and inextensible. Find the acceleration of centre of mass of both the blocks. Neglect friction everywhere.

Shown in the diagram is a system of two bodies, a block of mas m and a disc of mass M , held in equilibrium. If the string 3 is burnt, find the acceleration of the disc. Neglect the masses of the pulleys P and Q . (The coefficient of friction between the block and horizontal surface is mu )

In the figure-2.205 shown in blocks A, B and C has masses m_(A)= 5 kg, m_(B) = 5 kg and m_(C )= 10kg respectively, find the acceleration of the three blocks. Assume all pulleys and strings are ideal. (Take g = 10m//s^(2) )