A block of mass `2kg` is kept on the floor. The coefficient of static friction is `0.4` . If a force `F` of `2.5N` is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4.A force F of 2.5 N is applied on the block, as shown. Calculate the force of friction between the block and the floor. ("g = 9.8 ms"^(–2))

A block of mass 2 kg is placed on the floor . The coefficient of static friction is 0.4 . If a force of 2.8 N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = 10 m//s^(2) )

A block of mass 4 kg is kept on a rough horizontal surface. The coefficient of static friction is 0.8. If a force of 19 N is applied on the block parallel to the floor, then the force of friction between the block and floor is

A block of mass 2 kg is at rest on a floor . The coefficient of static friction between block and the floor is 0.54. A horizonatl force of 2.8 N is applied to the block . What should be the frictional force between the block and the floor ? ( take , g = 10 m//s^(2) )

When F = 2n, the frictional force between 10 kg block 5 kg block is

On a smooth horizontal surface a block A of mass 10kg is kept. On this block a second block B of mass 5kg is kept. The coefficient of friction between the two blocks is 0.4 .A horizontal force of 30N is applied on the lower block as shown. The force of friction between the blocks is

A block is lying static on the floor. The maximum value of static fictional force on the block is 10 N. If a horizontal force of 6 N is applied to the block,what will be the frictional force on the block?