A cubical block rests on an inclined plance of `mu = (1)/sqrt(3)` . Determine the angle at which the block just slides down the incline .

A cubical block rests on a plane of mu= sqrt(3) . The angle through which the plane be inclined to the horizontal so that the block just slides down will be -

A block of mass m is placed on a rough inclined plane of inclination theta kept on the floor of the lift. The coefficient of friction between the block and the inclined plane is mu . With what acceleration will the block slide down the inclined plane when the lift falls freely ?

A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

A block is placed on an inclined plane. The angle of inclination of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is

Figure shows a block kept on a rough inclined plane. The maximum external force down the incline for which the block remains at rest is 1 N while the maximum external force up the incline for which the block is at rest is 7 N. The coefficient of static friction mu is:

A frictionless inclined plane of length l having inclination theta is placed inside a lift which is accelerating downward with on acceleration a (ltg) . If a block is allowed to move down the inclined plane, from rest, then the time taken by the block to slide from top of the inclined plane to the bottom of the inclined plane is

A block of mass 10 kg is placed on an inclined plane when the angle of inclination is 30^(@) . The block just begins to slide down the plane. The force of static friction is