An elevator and its load wiegh a total of 1600 lb. Find the tension T in the supporting cable when the elevator, originally moving downwards at 20 ft/s is brought to rest with constant acceleration in a distance of 50 ft.

An elevator and its load weigh a total of 1600 kg. Find the tension T in the supporting cable when the elevator, originally moving downward at 20 m/s is brought to rest with constant acceleration in a distance of 50 m.

An elevator and its load weigh a total of 166 kg. Find the tension T in the supporting cable when the elevator, originally moving downwards at 20m//s is brought to rest with constant acceleration in a distance of 50 m.

An elevator and its load weigh a total of 800kg Find the tension T in the supporting cable when the elevator originally moving downwards at 20m//s is brought to rest with constant retardation in a distnce of 50m .

An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downwards at 10 ms^(-1) , is brought to rest with constant deceleration in a distance of 25 m, the tension in the supporting canble will be ( g=10 ms^(-2) )

An elevator weighs 4000kg When the upward tension in the supporting cable is 48000 N what is the upward acceleration? Starting from rest, how far does it rise in 3 seconds ?

A motor car starts from rest and accelerates uniformly for 10 s to a velocity of 20 ms^(-1) . It then runs at a constant speed and is finally brought to rest in 40 m with a constant acceleration. Total distance covered is 640 m. Find the value of acceleration, retardation and total tie taken.

An elevator cab of mass m=500 kg is descending with speed v_(i)=4.0m//s when its supporting cable begins to slip, allowing it to fall with constant acceleration vec(a)=vec(g)//5 . During the fall through a distance d=12 m, what is the work W_(g) done on the cab by the gravitational force vec(F)_(g) ?

An elevator weighing 5000 kg is moving upward and tension in the supporting cable is 5000 N . Find upward acceleration . Starting from rest , how far does it rise in 10 secound ?

A pendulum suspended from the ceiling of an elevator at rest has a time period of oscillation equal to T_(1) . When the elevator moves up with an acceleration a, the time period becomes T_(2) and when the elevator moves down with an acceleration a, its time period becomes T_(3) , then find the expression for T_(1) in terms of T_(2) and T_(3) .