Two blocks of mass 2.9 kg and 1.9 kg are suspended from a rigid support S by two inextensible wires each of length 1 meter, see fig. The upper wire has negligible mass and the lower wire has a uniform mass of `0.2kg//m`. The whole system of blocks wires and support have an upward acceleration of `0.2m//s^2`. Acceleration due to gravity is `9.8m//s^2`.

(i) Find the tension at the mid-point of the lower wire.
(ii) Find the tension at the mid-point of the upper wire.

Two block of mass 2.9 kg and 1.9 kg are suspended from a rigid support S by two inextensible wires each of length 1 m , as shown in figure.The upper wire has negligibible mass and the lower wires and support have an uniformly mass of 0.2 kg .The whole system of blocks, wire and support have an upwardds acceleration of 0.2 m//s^(2) . Accceleration due to gravity is 9.8 m//s^(2) . (a) Find the tension at the mid point of the lower wire. (b)Find the tension at the mid point of the upper wire.

Two blocks of masses 2.9 kg and 1.9 kg are suspended from a rigid support S by two inextensible wires each of length 1 m. The upper wire has negligible mass and the lower wire has a uniform mass of 0.2 kg/m. Thewhole system of block, wire and support have an upward acceleration of 0.2 m/s2. g = 9.8 m/s2. The tension at the mid-point of lower wire is-

As shown in Fig. 5-51, body C (2.9 kg) and body D (1.9 kg) are suspended from a rigid support by inextensible wires B and A, each of length 1.0 m. Wire B has negligible mass, wire A has a uniform density of 0.20 kg/m. The whole system undergoes an upward acceleration of magnitude 0.50" m"//"s"^(2) . Find the tension at the midpoint in (a) wire A and (b) wire B.

A metal wire of length L is suspended vertically from a rigid support. When a bob of mass M is attached to the lower end of wire, the elongation of the wire is l:

A mass of 1 kg is supended by a string. It is (i) lifted up with an acceleration 4.9 m//s^(2) (ii) lowered with an acceleration 4.9 m//s^(2) Then the ration of the tension in the string in the two cases is

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :

The mass of a lift is 600 kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is-

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .