The area of cross section of a steel wire `(Y=2.0 xx 10^(11) N//m^(2))` is `0.1 cm^(2)`. The force required to double is length will be

For steel Y=2xx10^(11) Nm^(-2) . The force required to double the length of a steel wire of area 1 cm^(2) is

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10^(–6) m^(2) and Y is 2 xx 10^(11) N//m^(2) . Increase in length of the wire will be -

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

The area of a cross section of steel wire is 0.1cm^2 and Young's modulus of steel is 2xx10^(11)Nm^-2 . The force required to strech by 0.1% of its length is

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

Young 's modulus of steel is 2.0 xx 10^(11)N m//(2) . Express it is "dyne"/cm^(2) .

The Young's modulus of a wire of length 2m and area of cross section 1 mm^(2) is 2 xx 10^(11) N//m^(2) . The work done in increasing its length by 2mm is

If young's modulus of steel is 2xx10^(11)N//m^(2) , then the force required to increase the length of a wire of cross section 1 cm^(2) by 1% will be

A copper wire (Y=10^(11) Nm^(-2)) of length 8 m and a steel wire (Y=2xx10^(11) Nm^(-2)) of length 4 m, each of 0.5 cm^(2) cross-section are fastened end to end and stretched with a tension of 500 N. choose the correct option.

If the interatomic spacing in a steel wire is 3.0 Å and Y_(steel)=20xx10^(10)N//m^(2) then force constant is