The breaking stress of a material is `10^(8)Nm^(-2)` . Find the greatest length of a wire that could hang vertically without breaking. Density of material`=3000kgm^(-3)`

The breaking stress of aluminium is 7.5 xx 10^7 Nm^(-2) Find the greatest length of aluminum wire that can hang vertically without breaking Density of aluminium is 2.7 xx 10^3 kg m^(-3)

The breaking stress of aluminimum is 7.5xx10^(8) dyne cm^(-2) find the greatest length of aluminium wire that can hang vertically without breaking density of aluminimum is 2.7gcmL^(-3) [given g=980cms^(-2) ]

If p is the density of the material of a wire and sigma the breaking stress, the greatest length of the wire that can hang freely without breaking is

The breaking stress for a metal is 7.8 xx 10^9 Nm^-2 . Calculate the maximum length of the wire of this metal which may be suspended breaking. The density of the metal = 7.8 xx 10^3kg m^-3 . Take g = 10 N kg^-1

The breaking stress for a substance is 10^(6)N//m^(2) . What length of the wire of this substance should be suspended verticaly so that the wire breaks under its own weight? (Given: density of material of the wire =4xx10^(3)kg//m^(3) and g=10 ms^(-12))

Breaking stress for a material is 2 xx 10^8 N//m^2 . What maximum length of the wire of this material can be taken t the wire does not break by own weight? Density of material = 5 xx 10^3 kg//m^3

if rho is the density of the meterial of a wire and sigma is the breaking stress. The greatest length of the wire that can hang freely without breaking is