A rubber string 10m long is suspended from a rigid support at its one end. Calculate the extension in the string due to its own weight. The density of rubber is `1.5xx10^(3)` and Young's modulus for the rubber is `5xx10^(6)Nm^(-2)` Take `g=10Nkg^(-1)` .

A rubber rope of length 8 m is hung from the ceiling of a room. What is the increase in length of rope due to its own weight? (Given: Young's modulus of elasticity of rubber = 5 xx 10^(6) N//m and density of rubber =1.5xx10^(3)kg//m^(3) . Take g=10ms^(-12))

A rubber rope of length 8 m is hung from the ceiling of a room. What is the increases in length of the rope due to its own weight? (Given, Young's modulus of elasticity of rubber = 5 xx 10^(6) Nm^(-2) and density of rubber = 1.5 xx 10^(6) kg m^(-3) and g = 10 ms^(-2) )

A rubber cord 10 m long is suspended vertically. How much does it stretch under its own weight (Density of rubber is 1500 kg//m, Y=5xx10 N//m,g = 10 m//s )

A uniform string of length 10 m is suspended from a rigid support A short wave pulse is introduced at its lowest end it starts moving up the string the time taken to reach the support is (take g=10m//sec^(2) )

A wire having a length 1 m and cross-section area 3mm^(2) is suspended at one of its ends from a ceiling. What will be its strain energy due to its own weight, if the density and Young's modulus of the material of the wire be 10 g//cm^(3) and 1.2xx10^(11)N//m^(2) respectively.

A 0.5 kg block of brass (density 8xx103Kg m^(-3) ) is suspended from a string. What is the tension in the string if the block is completely immersed in water? (g =10ms^(-2))

A wire of length l and cross-sectional are A is suspended at one of its ends from a ceiling. What will be its strain energy due to its own weight, if the density and Young's modulus of the material of the wire be d and Y?

A 5 kg mass is attached to one end of a copper wire 2m long and 2mm in diameter. Calculate the leteral compression produced in it. Posisson's ration is 0.3 and Young's modulus of the meterial of the wire is 12.5 xx 10^(10)Nm^(-2)

A uniform string of length 20m is suspended from a rigid support. A shirt wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is : (take g = 10ms^(-2) )