A wire of cross -sectional area `4 xx 10^(-4) m^(2)` , modulus of elasticity `2 xx 10^(11) Nm^(-2)` and length 1 m is stretched between two rigid poles . A mass of 1 kg is suspended at its middle . Calculate the angle it makes with horizontal . Take g = `10 ms^(-2)`

A 1 m long steel wire of cross-sectional area 1 mm^(2) is extended 1 mm. If Y = 2 xx 10^(11) Nm^(-2) , then the work done is

A mild steel wire of length 1.0 m and cross-sectional are 0.5 xx 10^(-20)cm^(2) is streached, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid point of the wire, calculate the depression at the mid point. g = 10ms^(-2), Y=2 xx 10^(11)Nm^(-2 .

A mild steel wire of length 1.0m and cross sectional area 5.0xx10^(-2)cm^(2) is stretched, within its elastic limit horizontally between two pillars. A mass of 100g is suspended form the midpont of the wire. Calculate the depression at the midpoint (Y_("steel) = 200GPa)

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

Young's modulus of a wire is 2 xx 10^(11) N//m^(2) . The wire is stretched by a 5 kg weight. If the radius of the wire is doubled, its Young's modulus

The area of a cross section of steel wire is 0.1cm^2 and Young's modulus of steel is 2xx10^(11)Nm^-2 . The force required to strech by 0.1% of its length is

A steal wire of cross-section area 3xx10^(-6) m^(2) can withstand a maximum strain of 10^(-3) .Young's modulus of steel is 2xx10^(11) Nm^(-2) .The maximum mass this wire can hold is

A wire 2 m in length suspended vertically stretches by. 10 mm when mass of 10 kg is attached to the lower end. The elastic potential energy gain by the wire is (take g = 10 m//s^(2) )

A copper wire of length 2m and area of cross-section 1.7 xx 10^(-6)m^(2) has a resistance of 2 xx 10^(-2) ohms. Calculate the resistivity of copper.