Velocity of flow of water in a horizontal pipe is `4.9 ms^(-1)` Find the velocity heat of water.

Answer

To find the velocity head of water flowing in a horizontal pipe, we can use the formula for kinetic energy per unit volume, which is related to the velocity head. The velocity head (h) can be calculated using the following steps:

### Step-by-Step Solution:

1. **Identify the given data**:
- Velocity of water, \( v = 4.9 \, \text{m/s} \)

2. **Understand the formula for velocity head**:
- The velocity head is given by the formula:
\[ h = \frac{v^2}{2g} \]
where \( g \) is the acceleration due to gravity.

3. **Substitute the value of \( g \)**:
- The standard value of \( g \) is approximately \( 9.8 \, \text{m/s}^2 \).

4. **Calculate \( v^2 \)**:
- First, calculate \( v^2 \):
\[ v^2 = (4.9)^2 = 24.01 \, \text{m}^2/\text{s}^2 \]

5. **Plug values into the formula**:
- Now substitute \( v^2 \) and \( g \) into the formula for \( h \):
\[ h = \frac{24.01}{2 \times 9.8} \]

6. **Calculate the denominator**:
- Calculate \( 2g \):
\[ 2g = 2 \times 9.8 = 19.6 \, \text{m/s}^2 \]

7. **Final calculation of \( h \)**:
- Now divide \( v^2 \) by \( 2g \):
\[ h = \frac{24.01}{19.6} \approx 1.225 \, \text{m} \]

### Conclusion:
The velocity head of the water is approximately \( 1.225 \, \text{m} \).