A hollow sphere and a solid sphere of equal radii and of same material are heated to raise their temperature by equal amounts. How will the change in their volume expansion be related?

We have a hollow sphere and a solid sphere equal radii and of the same material. They are heated to raise their temperature be equal amounts. How will the cange in their volumes, due to volume expansions, be related? Consider two cases (i) hollow sphere is filled with air, (ii) there is vaccum inside the hollow sphere.

A solid sphere and a hollow sphere of the same material and of equal radii are heated to the same temperature

A solid sphere and a hollow sphere of the same material and of equal radii are heated to the same temperature.

A nollow sphere and a solid sphere having same mass and same radii are rolled down a rough incline plane.

Assertion : A solid and hollow sphere of same diameter and same material when heated through the same temperature will expand by the same amount. Reason : The change in volume us independent of the original mass but depends on original volume.

A solide sphere and a hollow sphere of the same material and of equal radii are heated to the same temperature (i) Both will emit equal amount of radiation per unit time in the beginning (ii) Both will absorb equal amount of radiation from the surrounding in the beginning (iii) The initial rate of cooling dT//dt will be same for the two spheres (iv) The two spheres will have equal temperatures at any instant

A solid sphere and a hollow sphere of the same material and size are heated to the same temperature and allowed to cool in the same surroundings. If the temperature difference between the surroundings and each sphere is T, then :

A solid cube and a solid sphere of the same material have equal surface area. Both are at the same temperature 120^(@)C , then

A hollow and a solid sphere of same material and identical outer surface under identical condition are heated to the same temperature at the same time (both have same e, a):