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A lead bullet of mass 50g moving with a velocity of `100ms^(-1)` strikes a target. If `40%` of the heat produced is retained by the bullet, calculate the rise in its temperature. Specific heat of lead `= 0.03 cal g^(-1)K^(-1)` and `J = 4.2 J cal^(-1)`

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The correct Answer is:
`15.87^(@)C`
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